14x^2-4x-18=0

Solution for 14x^2-4x-18=0 equation:

14x^2-4x-18=0

a = 14; b = -4; c = -18;
Δ = b2-4ac
Δ = -42-4·14·(-18)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-32}{2*14}=\frac{-28}{28}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+32}{2*14}=\frac{36}{28}
=1+2/7
$